Answer
Dissociation of $NaNO_3$ in water:
$NaNO_3(s) -^{H_2O}- \gt Na^{+}(aq) + NO{_3}^{-}(aq)$
Work Step by Step
- When strong electrolytes are added to water they dissociate, which means that they will divide, producing their ions.
1. Identify the cation and the anion in $NaNO_3$
- Cation : 1 $Na^{+}$
- Anion: 1 $N{O_3}^{-}$
2. Write the equation for the dissociation:
$NaNO_3(s) -^{H_2O}- \gt Na^{+}(aq) + NO{_3}^{-}(aq)$
** Remember: the ions are dissociated in an aqueous solution, so, their state symbol is "(aq)".