Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 8 - Section 8.4 - Temperature and Pressure (Gay-Lussac's Law) - Questions and Problems - Page 267: 8.31b

Answer

168$^{\circ}$C

Work Step by Step

$T_{1}= (-18+273)K= 255\,K$ $P_{1}= 0.950\,atm= 0.950\,atm\times\frac{760\,torr}{1\,atm}$ $=722\,torr$ $P_{2}=1250\,torr$ According to Gay Lussac's law, if n and V are constant $\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ $\implies T_{2}=\frac{P_{2}T_{1}}{P_{1}}=\frac{1250\,torr\times255\,K}{722\,torr}=441\,K$ $=(441-273)^{\circ}C=168^{\circ} C$
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