Answer
The molar mass for $AlF_3$ is equal to 83.98 g.
Work Step by Step
1. Find the molar mass for each element in this compound:
$Al: 26.98g$
$F: 19.00g$
2. Multiply each one of them by their respective subscript number:
$Al: 26.98g $
$F: 19.00g * 3= 57.00g$
3. Calculate the total sum of these values:
$26.98g + 57.00g = 83.98g$
