Answer
1810 J, 434 cal
Work Step by Step
$\Delta T = 122^{o}C -246^{o}C = -124^{o}C$
Heat = mass x $\Delta T$ x SH
Heat (J)= 38g x $-124^{o}C$ x 0.385 J / g $^{o}C$
= 1,814 J
Heat (cal)= 38g x $-124^{o}C$ x 0.0920 cal / g $^{o}C$
= 433.5 cal