Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 8 - Sections 8.1-8.9 - Exercises - Problems by Topic: 70d



Work Step by Step

$S^{2-}$ has the larger radius because $S^{2-}$ and $Ca^{2+}$ are isoelectronic, meaning that they have the same number of electrons. However, $S^{2-}$ has four fewer protons than $Ca^{2+}$, resulting in a lesser pull on the electrons and therefore, a larger radius.
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