Chapter 7 - Sections 7.1-7.6 - Exercises - Cumulative Problems - Page 332: 80

$1.24\times10^{15}\,s^{-1}$

$E= 496\times10^{3}\,J/mol\times\frac{1\,mol}{6.022\times10^{23}}$ $=8.236466\times10^{-19}\,J$ $E=h\nu\implies \nu=\frac{E}{h}$ $=\frac{8.236466\times10^{-19}\,J}{6.626\times10^{-34}\,J\cdot s}$ $=1.24\times10^{15}\,s^{-1}$