Answer
$745 kWh$$\times\frac{3.60\times10^{6}}{1 kWh}$$\times\frac{1 Cal}{4184J}$$=6.41\times10^{6} Cal$
Work Step by Step
Use a conversion factor to convert from kilowatt-hours to joules. Then convert joules into Calories.
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 287: 36c
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