#### Answer

$745 kWh$$\times\frac{3.60\times10^{6}}{1 kWh}$$\times\frac{1 Cal}{4184J}$$=6.41\times10^{6} Cal$

#### Work Step by Step

Use a conversion factor to convert from kilowatt-hours to joules. Then convert joules into Calories.

Published by
Prentice Hall

ISBN 10:
0321809246

ISBN 13:
978-0-32180-924-7

$745 kWh$$\times\frac{3.60\times10^{6}}{1 kWh}$$\times\frac{1 Cal}{4184J}$$=6.41\times10^{6} Cal$

Use a conversion factor to convert from kilowatt-hours to joules. Then convert joules into Calories.

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