Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Conceptual Problems - Page 293: 137

Answer

$\Delta H=-2418\,J/mol$ $q=-2418\,J$ $w=-5\,J$ $\Delta E=-2423\,J/mol$

Work Step by Step

$\Delta H$ is negative as heat is evolved. $\Delta H=-2418\, J/mol$ At constant pressure, $\Delta H=q=-2418\,J$ Since work is done by the system, $w$ is negative. $w=-5\,J$ $\Delta E=q+w=(-2418\,J)+(-5\,J)$ $=-2423\,J/mol$
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