Chapter 5 - Sections 5.1-5.10 - Exercises - Review Questions - Page 238: 21

$KE_{avg}=\frac{3}{2}RT$ $v_{rms}=\sqrt{\frac{3RT}{M}}$

We know that kinetic energy is directly proportional to absolute temperature. Mathematically, we can express it as $KE_{avg}=\frac{3}{2}RT$ The root mean square velocity of a gas is inversely proportional to the square root of molar mass of the gas . We can express it as $v_{rms}=\sqrt{\frac{3RT}{M}}$