Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 23a


$Mg_{3}$$(PO_{4})_{2}$ 3 Magnesium atoms, 2 Potassium atoms, 8 Oxygen atoms

Work Step by Step

To determine the amount of atoms of each element, one must first determine the amount of elements in the molecule. Each uppercase letter represents a new element. So we have Mg, P, and O elements in the molecule. Then determine the amount of each atom by looking at the subscripts of each element. Therefore, Mg is 3. If there is a molecule that is denoted with a parentheses, then to determine the amount of each element in that molecule, multiply the subscript of the element by the subscript on the outside of the parentheses. Therefore, potassium would be 2, since 1 x 2 = 2 (one original potassium multiplied by 2, since that is the subscript outside the parentheses). Likewise, oxygen would be 4 x 2 = 8.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.