Answer
[Cr(H$_{2}$O)$_{6}$]$^{3+}$ H$_{2}$O is neutral, which means that Cr has an oxidation state of +3. Six H$_{2}$O molecules are attached to each Cr, which makes the coordination number to be 6.
Work Step by Step
[Cr(H$_{2}$O)$_{6}$]$^{3+}$ H$_{2}$O is neutral, which means that Cr has an oxidation state of +3. Six H$_{2}$O molecules are attached to each Cr, which makes the coordination number to be 6.
