Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 46


Number of electrons needed = $6.25\times10^{18}$ Total mass = $5.6875\times10^{-12}$ kg

Work Step by Step

Charge on 1 electron = $-1.6\times10^{-19}$ C Required charge = $-1$ C Number of electrons needed = $\frac{-1}{-1.6\times10^{-19}}$ = $6.25\times10^{18}$ Mass of $1$ electron = $9.1\times10^{-31}$ kg Thus, total mass = $6.25\times10^{18} \times 9.1\times10^{-31} $ = $5.6875\times10^{-12}$ kg
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