Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 947: 67a

Answer

Mass defect= 0.13701 amu Nuclear binding energy= 7.976 MeV/nucleon

Work Step by Step

Mass defect=8(mass $^{1}_{1}H$)+8(mass $^{1}_{0}n$)-mass $^{16}_{8}O$ =8(1.00783 amu)+8(1.00866 amu)- 15.994915 amu =0.13701 amu. Nuclear binding energy=$0.13701\,amu\times\frac{931.5\,MeV}{1\,amu}=127.62\,MeV$ Nuclear binding energy per nucleon= $\frac{127.62\,MeV}{16\,nucleons}=7.976\,MeV/nucleon$
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