Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Problems by Topic - Page 745: 33c


$KOH(aq)$ is a base according to the Arrhenius definition.

Work Step by Step

According to the Arrhenius definition, a base is a substance which produces $OH^-$ ions in an aqueous solution. As we can see from the below equation, $KOH(aq) \rightarrow K^+(aq) + OH^-(aq)$ $KOH$ produces $OH^-$ ions in aqueous solutions. So it is a base.
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