Answer
Please see the work below.
Work Step by Step
The integrated rate law for a zero-order is
$[A]=-kt+[A]_0$
The integrated rate law for a first order is given as
$\ln[A]=-kt+\ln[A]_0$
Now the integrated rate law for a second order reaction is written as
$\frac{1}{[A]}=kt+\frac{1}{[A]_0 }$
