Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 12 - Sections 12.1-12.8 - Exercises - Problems by Topic - Page 591: 83

Answer

26.1 atm

Work Step by Step

Molarity, M= Number of moles of solute$\div$ Volume of solution in L $=\frac{(24.6\div92.1)mol}{.250 L}$. Gas constant, R = $0.0821 L atm K^{-1} mol^{-1}$. Temperature, T= 298 K. Recall that osmotic pressure, Π= MRT=$\frac{(24.6\div92.1)mol}{.250 L}\times0.0821 L atm K^{-1} mol^{-1}\times298K= 26.1 atm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.