Answer
$1.74M$
Work Step by Step
First we determine the concentrated molarity
$M_{c}=(\frac{49.0g\space H_2SO_4}{100.0g\space soln})(\frac{1mol\space H_2SO_4}{98.078g\space soln})(\frac{1.39g\space soln}{1cm^3.soln})(\frac{1000cm^3.soln}{1L\space soln})=6.944M\space H_2SO_4$
Now we find the required molarity as
$M_D=\frac{M_CV_C}{V_D}$
We plug in the known values to obtain:
$M_D=\frac{(6.9444M)(25.0cm^3)}{99.8cm^3}=1.74M$
