Answer
36.7 kJ
Work Step by Step
$q= n\Delta H_{sub}$
$=50.0\,g\times\frac{1\,mol\,CO_{2}}{44.01\,g}\times\frac{32.3\,kJ}{1\,mol\,CO_{2}}$
$=36.7\,kJ$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 11 - Sections 11.1-11.13 - Exercises - Problems by Topic - Page 538: 80
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