Answer
$PF_3$ : polar
$SBr_2$ : nonpolar
$CHCl_3$ : polar
$CS_2$ : nonpolar
Work Step by Step
$PF_3$ is polar due to the presence of the lone pair on P atom.
$SBr_2$ is nonpolar because it is tetrahedral with symmetrical lone pairs on S atom.
$CHCl_3$ is polar due to different polarities of the C-Cl and C-H bonds.
$CS_2$ is nonpolar because it is linearly symmetrical.
