Answer
a. $Rb < Na < Be$
b. $Sr < Se < Ne$
c. $Fe < P < O$
Work Step by Step
a. The first ionization energy generally decreases with a higher principal quantum number and less number of valence electrons. Therefore, the order is $Rb < Na < Be$.
b. The first ionization energy generally decreases with a higher principal quantum number and less number of valence electrons. Therefore, the order is $Sr < Se < Ne$.
c. The first ionization energy generally decreases with a higher principal quantum number and less number of valence electrons. Therefore, the order is $Fe < P < O$.