Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 343: 56

Answer

$v=7300\frac{m}{s}$ ,$v=730,000\frac{m}{s}$

Work Step by Step

As $v=\frac{h}{m\lambda}$....eq(1) We plug in the known values in eq(1)to obtain: $v=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}(100\times 10^{-9})}$ $v=7300\frac{m}{s}$ We plug in the known values to obtain: $v=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}(1\times 10^{-9})}$ $v=730,000\frac{m}{s}$
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