## Chemistry 9th Edition

$v=7300\frac{m}{s}$ ,$v=730,000\frac{m}{s}$
As $v=\frac{h}{m\lambda}$....eq(1) We plug in the known values in eq(1)to obtain: $v=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}(100\times 10^{-9})}$ $v=7300\frac{m}{s}$ We plug in the known values to obtain: $v=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}(1\times 10^{-9})}$ $v=730,000\frac{m}{s}$