## Chemistry 9th Edition

$-220.8\text{ kJ}$
$C_{(s)}+O_{2(g)}\Rightarrow CO_{2(g)}$ -397.3 kJ/mol Carbon $2CO_{2(g)}\Rightarrow 2CO_{(g)}+O_{2(g)}$ 283.3 kJ/mol CO Therefore, $2C_{(s)}+2O_{2(g)}\Rightarrow 2CO_{2(g)}$ + $2CO_{2(g)}\Rightarrow 2CO_{(g)}+O_{2(g)}$= $2C_{(s)}+O_{2(g)}\Rightarrow 2CO_{(g)}$ and the enthalpy of the reaction is: $2*(-393.7)+566.6=-220.8\text{ kJ}$