## Chemistry 9th Edition

Partial Pressure of $He$: $0.066\text{ atm}$ Partial Pressure of $Ne$: $0.100\text{ atm}$ Partial Pressure of $Ar$: $0.118\text{ atm}$
Partial Pressure of $He$ $200.\text{ torr}*\frac{1 \text{ atm}}{760 \text{ torr}}=0.263\text{ atm}$ We must multiply the pressure of $He$ by $\frac{1}{4}$ to account for the change from 1 L to 4L. $0.263\text{ atm}*\frac{1}{4}=0.066\text{ atm}$ Partial Pressure of $Ne$ We must multiply the pressure of $Ne$ by $\frac{1}{4}$ to account for the change from 1 L to 4L. $0.400\text{ atm}*\frac{1}{4}=0.100\text{ atm}$ Partial Pressure of $Ar$ $24.0\text{ kPa}*\frac{1\text{ atm}}{101.325\text{ kPa}}=0.237\text{ atm}$ We must multiply the pressure of $Ar$ by $\frac{1}{2}$ to account for the change from 2 L to 4 L. $0.237\text{ atm}*\frac{1}{2}=0.118\text{ atm}$