Answer
Mol CoCl2 = 0.0125 mol
Mol NiCl2 = 0.00875 mol
Both CoCl2 and NiCl2 are soluble chloride salts. The total volume is 0.0750 L.
MCo2+ = 0.167 M; MNI2+ = 0.117 M
MCl- = 0.567 M
Work Step by Step
Mol CoCl2 = 0.0500 L × 0.250 mol CoCl2/L = 0.0125 mol
Mol NiCl2 = 0.0250 L × 0.350 mol NiCl2/L = 0.00875 mol
Both CoCl2 and NiCl2 are soluble chloride salts by the solubility rules. A 0.0125-mol
aqueous sample of CoCl2 is actually 0.0125 mol Co2+ and 2(0.0125 mol) = 0.0250 mol Cl−.
A 0.00875-mol aqueous sample of NiCl2 is actually 0.00875 mol Ni2+ and 2(0.00875) = 0.0175 mol Cl−. The total volume of solution that these ions are in is 0.0500 L + 0.0250 L = 0.0750 L.
MCo2+ = 0.0125 mol Co2+/0.0750 L = 0.167 M; MNI2+ = 0.00875 mol Ni2+/0.0750 L = 0.117 M
MCl- = 0.0250 mol Cl- + 0.0175 mol Cl / 0.0750 L = 0.567 M
