Answer
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Work Step by Step
Using Le Chatelier's principle, a decrease in pressure (volume increases) will favor the side with the greater number of particles. Thus 2 I(g) will be favored at low pressure.
Looking at ΔG: ΔG = ΔG° + RT ln (Pi^2/Pi2);
ln(Pi^2/Pi2)>0
Pi= Pi2 = 10 atm and ΔG is positive (not spontaneous). But at PI = Pi2 = 0.10 atm, the logarithm term is negative. If |RT ln Q| > ΔG°, then ΔG becomes negative, and the reaction is spontaneous.
