## Chemistry 9th Edition

The $HI$ concentration in this solution is equal to $3.2 \times 10^{-3}M$
Since $HI$ is a strong acid, $[H_3O^+] = [HI]_{initial}$ 1. Calculate the hydronium ion concentration in this solution: $[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 2.50}$ $[H_3O^+] = 3.2 \times 10^{- 3}M$ Therefore, $[HI]_{initial} = 3.2 \times 10^{-3}M$