Answer
$pOH=11.9$
$[H^+]=7.9*10^{-3}\text{ M}$
$[OH^-]=1.3*10^{-12}\text{ M}$
Work Step by Step
$pH+pOH=14$
$2.1+pOH=14\Rightarrow pOH=11.9$
$[H^+]=10^{-2.1}=7.9*10^{-3}\text{ M}$
$[OH^-]=10^{-11.9}=1.3*10^{-12}\text{ M}$
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 14 - Acids and Bases - Exercises - Page 703: 53
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