Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 14 - Acids and Bases - Exercises - Page 703: 53


$pOH=11.9$ $[H^+]=7.9*10^{-3}\text{ M}$ $[OH^-]=1.3*10^{-12}\text{ M}$

Work Step by Step

$pH+pOH=14$ $2.1+pOH=14\Rightarrow pOH=11.9$ $[H^+]=10^{-2.1}=7.9*10^{-3}\text{ M}$ $[OH^-]=10^{-11.9}=1.3*10^{-12}\text{ M}$
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