## Chemistry 9th Edition

a. $K = 0.11$ b. $K = 7.6 \times 10^1$ c. $K = 8.8$ d. $K = 1.7 \times 10^{-4}$
a. Since the coefficients for that reaction are equal to the half of the coefficients from the first reaction: $K = \sqrt {1.3 \times 10^{-2}} = 0.11$ b. Since we have inversed the equation: $K = \frac{1}{1.3 \times 10^{-2}} = 7.6 \times 10^1$ c. Since we have inversed and divided the equation by 2: $K = \frac{1}{\sqrt {1.3 \times 10^{-2}}} = 8.8$ d, Since we have multiplied the coefficients of the equation by 2: $K = (1.3 \times 10^{-2})^2 = 1.7 \times 10^{-4}$