Answer
$3.35\text{ g $Na_2C_2O_4$}$
Work Step by Step
$0.250\text{ L}*\frac{0.100\text{ mol $Na_2C_2O_4$}}{1\text{ L}}*\frac{134\text{ g $Na_2C_2O_4$}}{1\text{ mol $Na_2C_2O_4$}}=3.35\text{ g $Na_2C_2O_4$}$
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 11 - Properties of Solutions - Solution Review - Page 543: 12
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