Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 11 - Properties of Solutions - Solution Review - Page 543: 12


$3.35\text{ g $Na_2C_2O_4$}$

Work Step by Step

$0.250\text{ L}*\frac{0.100\text{ mol $Na_2C_2O_4$}}{1\text{ L}}*\frac{134\text{ g $Na_2C_2O_4$}}{1\text{ mol $Na_2C_2O_4$}}=3.35\text{ g $Na_2C_2O_4$}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.