Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 11 - Properties of Solutions - Solution Review: 12

Answer

$3.35\text{ g $Na_2C_2O_4$}$

Work Step by Step

$0.250\text{ L}*\frac{0.100\text{ mol $Na_2C_2O_4$}}{1\text{ L}}*\frac{134\text{ g $Na_2C_2O_4$}}{1\text{ mol $Na_2C_2O_4$}}=3.35\text{ g $Na_2C_2O_4$}$
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