Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 11 - Properties of Solutions - Exercises - Page 547: 71

Answer

$500\frac{g}{mol}$

Work Step by Step

We know that $m=\frac{\Delta T_f}{K_f}$ We plug in the known values to obtain: $m=\frac{2.63}{40}=6.6\times 10^{-2}mol$ We also know that $molar\space mass=\frac{mass}{no. \space of\space moles}$ We plug in the known values to obtain: $molar \space mass=\frac{1.00g}{0.0250Kg\space solvent \times \frac{6.62\times 10^{-2}mol}{Kg\space solvent}}=500\frac{g}{mol}$
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