#### Answer

$7.9M$

#### Work Step by Step

We know that
$molarity=\frac{moles \space of \space solute}{liter \space of \space solution}$
We plug in the known values to obtain:
$molarity=\frac{46mL\times 0.79\frac{g}{mL}\times \frac{1mol}{46.07g}}{100.0mL\times \frac{1L}{1000mL}}=7.9M$