Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 10 - Liquids and Solids - Exercises - Page 502: 78



Work Step by Step

We know that edge length a is $a=2\times 314=628pm$ As Molar mass of $KCl=74.5\frac{g}{mol}$ mass of 4 molecules $=\frac{4\times 74.5}{6.023\times 10^{23}}g$ Now $Density=\frac{4\times 74.5}{6.023\times 10^{23}\times (628\times10^{-10} )^3}$ $Density=2\frac{g}{cm^3}$
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