Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Exercises - Page 35: 36

Answer

a) $2.26$ b) $8.43\times10^{22}$ c) $1.5\times 10^5$ d) $6.67\times 10^{12}$

Work Step by Step

a) $\frac{0.102\times 0.0821\times 273}{1.01}\approx 2.2635$. Since all terms have 3 significant figures, the answer also has 3 significant figures b) $0.14\times 6.022\times 10^{23}\approx 8.4308\times10^{22}$. Since the first term ($0.14$) has 2 significant figures, the answer also has 2 significant figures. c) $4.0\times 10^4\times 5.021\times 10^{-3}\times 7.34993\times 10^2\approx 1.4762\times 10^5$. Since the first term ($4.0$) has 2 significant figures, the answer also has 2 significant figures. d) $\frac{2.00\times 10^6}{3.00\times 10^{-7}}\approx 6.6667\times 10^{12}$. Since both terms have 3 significant figures, the answer also has 3 significant figures.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.