Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Challenge Problems: 111

Answer

a) Percentage error = 2.222 % b) Percentage error = 2.233 % c) Percentage error = 0.19 %

Work Step by Step

a) Given: True value of density = 2.70 $\frac{g}{cm^{3}}$ Experimental value of density = 2.64 $\frac{g}{cm^{3}}$ Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100 = $\frac{|2.70 - 2.64|}{2.70}$ $\times$ 100 = $\frac{0.06}{2.7}$ $\times$ 100 = $\frac{6}{2.7}$ = 2.22 % b) Given: True value of iron= 16.12 % Experimental value of iron = 16.48 % Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100 = $\frac{|16.12 - 16.48|}{16.12}$ $\times$ 100 = $\frac{0.36}{16.12}$ $\times$ 100 = $\frac{36}{16.12}$ = 2.233 % c) Given: True value of mass= 1.0 gram Experimental value of mass = 0.9981 gram Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100 = $\frac{|0.9981 - 1.00|}{1}$ $\times$ 100 = $\frac{0.0019}{1}$ $\times$ 100 = $\frac{0.19}{1}$ = 0.19 %
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