Answer
a) Percentage error = 2.222 %
b) Percentage error = 2.233 %
c) Percentage error = 0.19 %
Work Step by Step
a) Given: True value of density = 2.70 $\frac{g}{cm^{3}}$
Experimental value of density = 2.64 $\frac{g}{cm^{3}}$
Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100
= $\frac{|2.70 - 2.64|}{2.70}$ $\times$ 100
= $\frac{0.06}{2.7}$ $\times$ 100
= $\frac{6}{2.7}$
= 2.22 %
b) Given: True value of iron= 16.12 %
Experimental value of iron = 16.48 %
Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100
= $\frac{|16.12 - 16.48|}{16.12}$ $\times$ 100
= $\frac{0.36}{16.12}$ $\times$ 100
= $\frac{36}{16.12}$
= 2.233 %
c) Given: True value of mass= 1.0 gram
Experimental value of mass = 0.9981 gram
Thus percent error = $\frac{|True Value - Experimental Value|}{True Value}$ $\times$ 100
= $\frac{|0.9981 - 1.00|}{1}$ $\times$ 100
= $\frac{0.0019}{1}$ $\times$ 100
= $\frac{0.19}{1}$
= 0.19 %
