Answer
$8.0g$ Sr
Work Step by Step
$1m^{3}seawater\times\frac{1000 dm^{3}seawater}{1m^{3}seawater}\times\frac{1L}{1dm^{3}}\times\frac{1000mL}{1L}\times\frac{1.0g}{1mL}\times\frac{1kg}{1000g}\times\frac{8.0\times10^{-1}cgSr}{1 kg}\times\frac{10^{-2}g}{1cg} = 8.0gSr$
