Chemistry (12th Edition)

Published by Prentice Hall

Chapter 3 - Scientific Measurement - 3 Assessment - Page 98: 104

Answer

$8.0g$ Sr

Work Step by Step

$1m^{3}seawater\times\frac{1000 dm^{3}seawater}{1m^{3}seawater}\times\frac{1L}{1dm^{3}}\times\frac{1000mL}{1L}\times\frac{1.0g}{1mL}\times\frac{1kg}{1000g}\times\frac{8.0\times10^{-1}cgSr}{1 kg}\times\frac{10^{-2}g}{1cg} = 8.0gSr$

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