## Chemistry (12th Edition)

Volume of water=$158 cm^{3}$. Density of ethanol=$0.804 g/cm^{3}$.
Density of water is 1000 $g/cm^{3}$ at 4 degrees C. So, the flask can hold $158 g \times\frac{1cm^{3}}{1g}=158 cm^{3}$. Now, if the 158 $cm^{3}$ flask contains 127 g ethanol, then density is = $\frac{127g}{158cm^{3}}=0.804 g/cm^{3}$.