Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 25 - Nuclear Chemistry - 25 Assessment: 66

Answer

a) $^{231}_{91}Pa$ -> $^{277}_{89}Ac + ^{4}_{2}He$ b) $^{241}_{95}Pa$ -> $^{237}_{93}Ac + ^{4}_{2}He$ c) $^{226}_{88}Ra$ -> $^{222}_{86}Rn + ^{4}_{2}He$ d) $^{252}_{99}Es$ -> $^{248}_{97}Bk + ^{4}_{2}He$

Work Step by Step

a) $^{231}_{91}Pa$ -> $^{277}_{89}Ac + ^{4}_{2}He$ b) $^{241}_{95}Pa$ -> $^{237}_{93}Ac + ^{4}_{2}He$ c) $^{226}_{88}Ra$ -> $^{222}_{86}Rn + ^{4}_{2}He$ d) $^{252}_{99}Es$ -> $^{248}_{97}Bk + ^{4}_{2}He$
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