Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 21 - Electrochemistry - 21 Assessment: 62

Answer

a) Oxidation: 6Cl$^{-}$(l) --> 3Cl$_{2}$(g) + 6e$^{-}$ (anode) Reduction: 2Al$^{3+}$(l) + 6e$^{-}$ --> 2Al(l) (cathode) b) 2AlCl$_{3}$(l) --> 2Al(l) + 3Cl$_{2}$(g) c) Chlorine gas is produced at anode. Liquid aluminum is produced at cathode.

Work Step by Step

a) Oxidation: 6Cl$^{-}$(l) --> 3Cl$_{2}$(g) + 6e$^{-}$ (anode) Reduction: 2Al$^{3+}$(l) + 6e$^{-}$ --> 2Al(l) (cathode) b) 2AlCl$_{3}$(l) --> 2Al(l) + 3Cl$_{2}$(g) c) Chlorine gas is produced at anode. Liquid aluminum is produced at cathode.
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