Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 21 - Electrochemistry - 21.2 Half-Cells and Cell Potentials - 21.2 Lesson Check - Page 743: 17

Answer

Ecell = -.71

Work Step by Step

2Al$^3$ + 3Mg --> 2Al + 3 Mg$^2$ Reduced: 9Mg -> 9Mg$^2$ + 6e- Oxidated: 4Al$^3$ + Ge -> 4Al 9 Mg + 4Al$^3$ --> 9Mg$^2$ + 4Al Ecell = -2.37 - (-1.66) Ecell = -.71
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.