# Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 688: 129

$m_1v_1=m_2v_2$ $2.5m\times1.50L = 8.0m\times v_2$ $v_2=0.47L$

#### Work Step by Step

$m_1v_1=m_2v_2$ $2.5m\times1.50L = 8.0m\times v_2$ $v_2=0.47L$

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