Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 685: 82



Work Step by Step

HNO2+H2O=NO2^- + H3O^+ Write the dissociation equation -log[H^+]=1.83 [H^+]=1.47*10^-2 use the pH to solve for Hydrogen ion concentration (which is also the hydronium ion concentration. Reaction: HNO2, NO2^-, H30^+ Initial: .50M, 0M, 0M Change:-1.47*10^-2, +1.47*10^-2, +1.47*10^-2 Equilibrium: .485, 1.47*10^-2, 1.47*10^-2 Create a RICE chart to find equilibrium amounts Ka= (1.47*10^-2)(1.47*10^-2)/.485 Plug equilibrium values into the equation Ka=[H^+][A^-]/[HA]
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