Answer
a) Ka = $\frac{[H^-][F^-]}{HF}$
b) a) Ka = $\frac{[H^+][HCO^-_3]}{H_2CO_3}$
Work Step by Step
a) Ka = $\frac{[H^-][F^-]}{HF}$
b) a) Ka = $\frac{[H^+][HCO^-_3]}{H_2CO_3}$
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 684: 69
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