Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 18 - Reaction Rates and Equilibrium - 18 Assessment: 93

Answer

In terms of grams: 9.64 x 10^-03 (Mols/Liter) x [87.6 + 12 + 48] (g/Mols) = 9.64 x 10^-03 x (147.6) ~ 1.42 g / Liter with 147.6 equal to the Formula Weight of the SrCO3.

Work Step by Step

In terms of grams: 9.64 x 10^-03 (Mols/Liter) x [87.6 + 12 + 48] (g/Mols) = 9.64 x 10^-03 x (147.6) ~ 1.42 g / Liter with 147.6 equal to the Formula Weight of the SrCO3.
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