Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 18 - Reaction Rates and Equilibrium - 18 Assessment - Page 639: 93

Answer

In terms of grams: 9.64 x 10^-03 (Mols/Liter) x [87.6 + 12 + 48] (g/Mols) = 9.64 x 10^-03 x (147.6) ~ 1.42 g / Liter with 147.6 equal to the Formula Weight of the SrCO3.

Work Step by Step

In terms of grams: 9.64 x 10^-03 (Mols/Liter) x [87.6 + 12 + 48] (g/Mols) = 9.64 x 10^-03 x (147.6) ~ 1.42 g / Liter with 147.6 equal to the Formula Weight of the SrCO3.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions