## Chemistry (12th Edition)

Published by Prentice Hall

# Chapter 18 - Reaction Rates and Equilibrium - 18 Assessment - Page 638: 66

#### Answer

$K_{eq}$ = $\frac{[[H_{2}S]^{2} [CH_{4}]]}{[H_{2}]^{4} [CS_{2}]}$

#### Work Step by Step

To write an equation for the equilibrium constant, write the products with their coefficients as superscripts in the numerator of the expression, and likewise with the reactants with their coefficients as superscripts in the denominator of the expression.

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