## Chemistry (12th Edition)

Radio wave is an electromagnetic spectrum wave with a wave speed (velocity) of 3 $\times$ $10^{8}$ m/s. The given frequency is 93.1 $\times$ $10^{6}$s$^{-1}$. As we have the velocity and frequency, we can use V = F x C (Velocity = Frequency x Wavelength). V= 3 $\times$ $10^{8}$ m/s F= 93.1 $\times$ $10^{6}$s$^{-1}$ C = ? V = F x C 3 $\times$ $10^{8}$ m/s = (93.1 $\times$ $10^{6}$s$^{-1}$) x ? To get ? by itself, we must divide both sides by (93.1 $\times$ $10^{6}$s$^{-1}$): $\frac{ 3 \times10^{8}m/s}{(93.1 \times 10^{6}s)}$ = ? Now, simply solve for the ?: $\frac{ 3 \times10^{8}m/s}{(93.1 \times 10^{6}s)}$ = ? --> Cancel out $10^{6}$ from $10^{8}$ in numerator. $\frac{ 3 \times10^{2}}{93.1 s}$ = $\frac{300 m/s}{93.1 s}$ $\approx$ 3.22 m