## Chemistry (12th Edition)

Published by Prentice Hall

# Chapter 16 - Solutions - 16 Assessment - Page 550: 94

#### Answer

96.9g chloride, 54.1g sodium. 6.43g magnesium. 2.07g calcium, and 1.99g potassium in 5.0L of seawater.

#### Work Step by Step

In this question, we will use the concept of molarity to back-calculate the grams of five different solutes found in 5.0L of sea water from their molar concentrations. The five solutes and their molarities are as follows: • Chloride - 0.546M • Sodium - 0.470M • Magnesium - 0.053M • Calcium -0.0103M • Potassium - 0.0102M Once we establish the solubility parameters of a solute, the next thing that concerns us is how much of the solute is dissolved in how much of the solvent - the concentration. The primary measure of concentration is molarity - a measure of how many moles of a solute are dissolved in a liter of solution. We calculate molarity as follows: We first must discuss wtiat molarity indicates. Saying that a solution is 0.546M chloride means there are 0.546 moles of chloride ions in one liter of the solution. By this logic, as we have five liters, we have ( or 2.73 moles of chloride ions in our sample of seawater. By this same logic, we have the following amounts of moles for our other solutes: • Sodium - • Magnesium - • Calcium - Potassium - From here, we convert our moles to grams using molar masses for each element taken from the periodic table as follows:

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