Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 14 - The Behavior of Gases - 14 Assessment - Page 484: 115

Answer

158.1658 g/mol 97.9951 g/mol 342.2956 g/mol 331.2098 g/mol

Work Step by Step

Use the periodic table to compute the molar mass of calcium acetate. 40.078 g/mol + 4(12.0107 g/mol) + 6(1.0079 g/mol) + 4(15.9994 g/mol) = 158.1658 g/mol Use the periodic table to compute the molar mass of phosphoric acid. 3(1.0079 g/mol) + 30.9738 g/mol + 4(15.9994 g/mol) = 97.9951 g/mol Use the periodic table to compute the molar mass of C12H22O11. 12(12.0107 g/mol) + 22(1.0079 g/mol) + 11(15.9994 g/mol) = 342.2956 g/mol Use the periodic table to compute the molar mass of lead(II) nitrate. 207.2 g/mol + 2(14.0067 g/mol) + 6(15.9994 g/mol) = 331.2098 g/mol
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