Answer
$V_1 = 15L$; $T_1 = 650K$; $V_2=5L$
$T_2=\frac{V_2T_1}{V_1}$
$T_2=216\frac{2}{3}K$
Work Step by Step
$V_1 = 15L$; $T_1 = 650K$; $V_2=5L$
$T_2=\frac{V_2T_1}{V_1}$
$T_2=216\frac{2}{3}K$
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 14 - The Behavior of Gases - 14 Assessment - Page 480: 58
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