Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 12 - Stoichiometry - 12 Assessment: 78

Answer

87.4 percent

Work Step by Step

84.4 grams Calcium Carbonate / 100.1 grams Calcium Carbonate = 0.843 moles Calcium Carbonate Finding the number of moles of Calcium Carbonate reacted 0.843 moles Calcium Carbonate x 1 mole Calcium Chloride = 0.843 moles Calcium Chloride use the mole ratio to convert moles of Calcium Carbonate to moles of Calcium Chloride 0.843 moles Calcium Chloride x 110 grams Calcium Chloride = 92.73 grams Calcium Chloride Find theoretical yield of Calcium Chloride 81.1 grams Calcium Chloride / 92.73 gras Calcium Chloride = 87.4 percent Divide actual yield by Theoretical yield to find percent yield
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