Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 12 - Stoichiometry - 12 Assessment: 58

Answer

87.1% yield

Work Step by Step

75.0 g FeCO3 x (1 mol FeCO3/115.86 g FeCO3) * (1 mol Fe2O3/2 mol FeCO3) * (159.7 g FeCO3/ 1 mol Fe2O3) = 51.6895, which is a 87.1% yield
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